https://cve.radiocsirt.org Contains only the most 10 recent entries. http://www.rssboard.org/rss-specification python-feedgen en Fri, 23 Oct 2026 16:00:53 +0000 https://cve.radiocsirt.org/vuln/euvd-2026-204815 EUVD-2026-204815 https://cve.radiocsirt.org/vuln/euvd-2026-204815 https://cve.radiocsirt.org/vuln/fkie_cve-2023-50259 <p>Medusa is an automatic video library manager for TV shows. Versions prior to 1.0.19 are vulnerable to unauthenticated blind server-side request forgery (SSRF). The `testslack` request handler in `medusa/server/web/home/handler.py` does not validate the user-controlled `slack_webhook` variable and passes it to the `notifiers.slack_notifier.test_notify` method, then `_notify_slack` and finally `_send_slack` method, which sends a POST request to the user-controlled URL on line 103 in `/medusa/notifiers/slack.py`, which leads to a blind server-side request forgery (SSRF). This issue allows for crafting POST requests on behalf of the Medusa server. Version 1.0.19 contains a fix for the issue.</p> <p>Medusa is an automatic video library manager for TV shows. Versions prior to 1.0.19 are vulnerable to unauthenticated blind server-side request forgery (SSRF). The `testslack` request handler in `medusa/server/web/home/handler.py` does not validate the user-controlled `slack_webhook` variable and passes it to the `notifiers.slack_notifier.test_notify` method, then `_notify_slack` and finally `_send_slack` method, which sends a POST request to the user-controlled URL on line 103 in `/medusa/notifiers/slack.py`, which leads to a blind server-side request forgery (SSRF). This issue allows for crafting POST requests on behalf of the Medusa server. Version 1.0.19 contains a fix for the issue.</p> https://cve.radiocsirt.org/vuln/fkie_cve-2023-50259 https://cve.radiocsirt.org/vuln/gsd-2023-50259 gsd-2023-50259 https://cve.radiocsirt.org/vuln/gsd-2023-50259